If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
5^x = 0
5^x = 0
5^x = 0
x należy do O
x in (-oo:+oo)
1/(5^x) = 0
1/(5^x) = 0 // * 5^x
1 = 0
x belongs to the empty set
| 13m=-22+48 | | 3x^4-4x^2+27x+6=0 | | 10ln(L)=0 | | cot^2x-1= | | Log(4)256=4 | | 2b+3b-4=o | | 8x(x)+5=20 | | 5x+3+6y=45 | | (0.8+x)(3.6+x)=0.113(1.4-x)(-x) | | x-21=2x+30 | | b(b)+3b-4=0 | | 2x-3=25.8 | | 11z-5=3y-10 | | -3.4k-7+3k+21= | | 81x^(4/5)=256 | | 3.71(4.8-x)(1.2-x)=0 | | 0.298ml= | | 256x^(4/3)=81 | | h(t)=-15t^2+60t+40 | | (x-2)(x-2-3i)(x-2+3i)(x+1-i)(x+1+i)=0 | | (7x+2)(5x+14)=0 | | x^5+5x^4+12x^3+8x^2=0 | | 5(x-4)+3=8(x+4)-36 | | 10d-8=d+1 | | 1-2x+4=0 | | 4(3x-4/9)=3 | | x+5=87-x | | 9.39(1.6-x)(2.4-x)=0 | | x/3=x-24 | | 4x-6=9y | | 5.84(3-x)(-x)=0 | | 256x^4/3=81 |